One family of 20 members have 20 chapatis to eat, finally

Every child gets 1/2 chapati.

Every Lady in the house gets 2 chapatis.

And every gentleman gets 3 chapatis to eat.

How many Child, Ladies and Gents are there in the family?

Lets assume number of children are X

number of ladies are Y

number of gents are Z

X+Y+Z = 20 ;

1/2 x + 2 Y + 3 Z = 20 ;

and X,Y,Z are integers and greater then or equal to zero.

Now we can deduce -

X is even

y < 10 and Z < 6

Now try trial and error after removing one variable from able two equations (i.e. 3y+5z = 20) which gives as y=0 & z=4 and y=5 & z=1. Second solution fits in the above equations so,

Every child gets 1/2 chapati.

Every Lady in the house gets 2 chapatis.

And every gentleman gets 3 chapatis to eat.

How many Child, Ladies and Gents are there in the family?

**Answer with Logic :**Lets assume number of children are X

number of ladies are Y

number of gents are Z

**Now**X+Y+Z = 20 ;

1/2 x + 2 Y + 3 Z = 20 ;

and X,Y,Z are integers and greater then or equal to zero.

Now we can deduce -

X is even

y < 10 and Z < 6

Now try trial and error after removing one variable from able two equations (i.e. 3y+5z = 20) which gives as y=0 & z=4 and y=5 & z=1. Second solution fits in the above equations so,

**number of children X = 14****number of ladies Y = 5****number of gents Z = 1**
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